Решебник по алгебре 7 класс Мерзляк ФГОС Задание 806

 

\[\boxed{\text{806\ (806).\ }\text{Еуроки\ -\ ДЗ\ без\ мороки}}\]

\[f(x) = \left\{ \begin{matrix} - 2x + 1,\ \ x \leq - 2 \\ x^{2},\ \ \ \ \ \ \ \ \ \ - 2 < x < 3 \\ 6,\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ x \geq 3\ \\ \end{matrix} \right.\ \]

\[1)\ f( - 3) = - 2 \cdot ( - 3) + 1 =\]

\[= 6 + 1 = 7\]

\[2)\ f( - 2) = - 2 \cdot ( - 2) + 1 =\]

\[= 4 + 1 = 5\]

\[3)\ f(2) = 2² = 4\]

\[4)\ f(3) = 6\]

\[5)\ f(2,9) = {2,9}^{2} = 8,41\]

\[6)\ f(8,1) = 6\]

\[\boxed{\text{806.\ }\text{Еуроки\ -\ ДЗ\ без\ мороки}}\]

\[1)\ a³ + 8 =\]

\[= (a + 2)(a^{2} - 2a + 4)\]

\[2)\ c³ - 64 =\]

\[= (c - 4)(c^{2} + 4c + 16)\]

\[3)\ 125 - b^{3} =\]

\[= (5 - b)(25 + 5b + b^{2})\]

\[4)\ 1 + x³ = (1 + x)(1 - x + x^{2})\]

\[5)\ a³ + 1000 =\]

\[= (a + 10)(a^{2} - 10a + 100)\]

\[6)\ 27a³ - 1 =\]

\[= (3a - 1)(9a^{2} + 3a + 1)\]

\[7)\ 1000c³ - 216 =\]

\[= (10c - 6)(100c^{2} + 60c + 36)\]

\[8)\ a³b³ - 1 =\]

\[= (ab - 1)(a^{2}b^{2} + ab + 1)\]

\[9)\ m³n³ + 0,001 =\]

\[= (mn + 0,1)(m^{2}n^{2} - 0,1mn + 0,01)\]

\[10)\frac{64}{343}m³ - \frac{125}{216}n^{3} =\]