Решебник по алгебре 7 класс Мерзляк Задание 270

\[\boxed{\text{270\ (}\text{н}\text{).}\text{\ }\text{Еуроки\ -\ ДЗ\ без\ мороки}}\]

\[1) - 4m^{3} \cdot 0,25m^{6} = - 1m^{9} =\]

\[= - m^{9}\]

\[2)\ 56x^{5}y^{14} \cdot \frac{2}{7}x^{2}y =\]

\[= 56 \cdot \frac{2}{7}x^{7}y^{15} = 16x^{7}y^{15}\]

\[3) - \frac{1}{3}p^{2} \cdot ( - 27k) \cdot 5pk =\]

\[= \frac{1}{3} \cdot 27 \cdot 5 = 9 \cdot 5 \cdot p^{3}k^{2} =\]

\[= 45p^{3}k^{2}\]

\[4)\ 2\frac{1}{4}b^{2}c^{5}d^{3} \cdot \left( - 3\frac{1}{3}b^{3}c^{4}d^{7} \right) =\]

\[= - \frac{9 \cdot 10}{4 \cdot 3}b^{5}c^{9}d^{10} =\]

\[= - 7,5b^{5}c^{9}d^{10}\]

\[\boxed{\text{270\ (}\text{с}\text{).}\text{\ }\text{Еуроки\ -\ ДЗ\ без\ мороки}}\]

\[1)\ 12a^{2} \cdot 5a^{3}b^{7} = 60a^{5}b^{7}\]

\[2) - 4m^{3} \cdot 0,25m^{6} = - 1m^{9} =\]

\[= - m^{9}\]

\[3)\ 3ab \cdot \left( - 17a^{2}b \right) = - 51a^{3}b^{2}\]

\[4)\ 56x^{5}y^{14} \cdot \frac{2}{7}x^{2}y = 16x^{7}y^{15}\]

\[5) - \frac{1}{3}p^{2} \cdot ( - 27k) \cdot 5pk =\]

\[= 45p^{3}k^{2}\]

\[6)\ 2\frac{1}{4}b^{2}c^{5}d^{3} \cdot \left( - 3\frac{1}{3}b^{3}c^{4}d^{7} \right) =\]

\[= - \frac{9 \cdot 10}{4 \cdot 3}b^{5}c^{9}d^{10} =\]

\[= - 7,5b^{5}c^{9}d^{10}\]