Решебник по алгебре 7 класс Мерзляк ФГОС Задание 1122

 

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\[Пусть\ число\ \overline{\text{xy}},\ тогда\]

\[\ \overline{\text{xy}} = 10x + y,\ x > y,\ тогда:\]

\[(10x + y)\ :(x - y) = 14,\ ост\ 2\]

\[14 \cdot (x - y) + 2 = 10x + y\]

\[14x - 14y + 2 = 10x + y\]

\[4x - 15y = - 2,\ \ тогда\]

\[тогда\ число\ 72.\]

\[Ответ:72.\ \ \ \]

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\[\ \ 0 + y = 2;\ \ y = 2 \Longrightarrow \ (0;2);\]

\[x + 0 = 2;\ \ x = 2 \Longrightarrow \ \ (2;0).\]

\[0 - y = 1;\ \ y = - 1 \Longrightarrow (0; - 1);\]

\[x^{3} - 0 = 1;\ \ x^{3} = 1;\ \ \ x = 1 \Longrightarrow \ \]

\[\Longrightarrow \ (1;0).\]

\[0 + y^{2} = 9;\ \ y^{2} = 9;\ \ y = \pm 3 \Longrightarrow \text{\ \ }\]

\[\Longrightarrow (0;3),(0;\ - 3);\]

\[x^{2} + 0 = 9;\ \ x^{2} = 9,;\ x = \pm 3 \Longrightarrow \ \]

\[\Longrightarrow (3;0),\ ( - 3;0).\]

\[0 - y = 5;\ \ y = - 5 \Longrightarrow \text{\ \ }(0;\ - 5);\]

\[|x| - 0 = 5;\ \ |x| = 5;\ \ x = \pm 5 \Longrightarrow \ \ \]

\[\Longrightarrow (5;0),\ ( - 5;0).\]