\[\frac{x^{2} - x - 6}{- 7 - x^{2}} > 0\]
\[1)\ x^{2} - x - 6 = 0\]
\[D = 1 + 24 = 25\]
\[x_{1} = \frac{1 - 5}{2} = - 2;\]
\[x_{2} = \frac{1 + 5}{2} = 3.\]
\[2)\ \frac{(x + 2)(x - 3)}{- 7 - x^{2}} > 0\]
\[\frac{(x + 2)(x - 3)}{7 + x^{2}} < 0\]
\[(x + 2)(x - 3) < 0\]
\[- 2 < x < 3.\]
\[Ответ:\ \ x = - 1.\]