Решебник по алгебре и начала математического анализа 11 класс Колягин Задание 79

\[1)\ tg\frac{\pi}{5}\ и\ \text{tg}\frac{\pi}{7}\]

\[- \frac{\pi}{2} < \frac{\pi}{7} < \frac{\pi}{5} < \frac{\pi}{2}\]

\[\text{tg}\frac{\pi}{5} > tg\frac{\pi}{7}.\]

\[2)\ ctg\frac{7\pi}{8}\ и\ \text{ctg}\frac{8\pi}{9}\]

\[0 < \frac{7\pi}{8} < \frac{8\pi}{9} < \pi\]

\[\text{ctg}\frac{7\pi}{8} > ctg\frac{8\pi}{9}.\]

\[3)\ tg\left( - \frac{7\pi}{8} \right)\ и\ \text{tg}\left( - \frac{8\pi}{9} \right)\]

\[- \frac{3\pi}{2} < - \frac{8\pi}{9} < - \frac{7\pi}{8} < - \frac{\pi}{2}\]

\[\text{tg}\left( - \frac{7\pi}{8} \right) > tg\left( - \frac{8\pi}{9} \right).\]

\[4)\ tg\left( - \frac{\pi}{5} \right)\ и\ \text{tg}\left( - \frac{\pi}{7} \right)\]

\[- \frac{\pi}{2} < - \frac{\pi}{5} < - \frac{\pi}{7} < \frac{\pi}{2}\]

\[\text{tg}\left( - \frac{\pi}{5} \right) < tg\left( - \frac{\pi}{7} \right).\]

\[5)\ ctg\ 2\ и\ \text{ctg}\ 3\]

\[0 < 2 < 3 < \pi\]

\[ctg\ 2 > ctg\ 3.\]

\[6)\ tg\ 1\ и\ \text{tg}\ 1,5\]

\[- \frac{\pi}{2} < 1 < 1,5 < \frac{\pi}{2}\]

\[tg\ 1 < tg\ 1,5.\]