\[1)\ \left\{ \begin{matrix} y - 1 = \sin x \\ y = \sqrt{x - \frac{\pi}{2}}\text{\ \ \ } \\ \end{matrix} \right.\ \]
\[y = \sin x + 1.\]
\[Ответ:\ \ да.\]
\[2)\ \left\{ \begin{matrix} y = - \sin x\text{\ \ \ } \\ y = - \frac{2}{x^{2}} - 1 \\ \end{matrix} \right.\ \]
\[Ответ:\ \ нет.\]