Решебник по алгебре и начала математического анализа 11 класс Колягин Задание 6

\[1)\ y = \frac{1}{2\sin^{2}x - \sin x}\]

\[2\sin^{2}x - \sin x \neq 0\]

\[\sin x \bullet \left( 2\sin x - 1 \right) \neq 0\]

\[\sin x \neq 0\ \]

\[x \neq \pi\text{n.\ \ \ }\]

\[\sin x \neq \frac{1}{2}\]

\[x \neq ( - 1)^{n} \bullet \frac{\pi}{6} + \pi n.\]

\[2)\ y = \frac{2}{\cos^{2}x - \sin^{2}x}\]

\[\cos^{2}x - \sin^{2}x \neq 0\]

\[\cos{2x} \neq 0\]

\[2x \neq \frac{\pi}{2} + \pi n\]

\[x \neq \frac{\pi}{4} + \frac{\pi n}{2}.\]

\[3)\ y = \frac{1}{\sin x - \sin{3x}}\]

\[\sin x - \sin{3x} \neq 0\]

\[2\sin( - x) \bullet \cos{2x} \neq 0\]

\[\sin( - x) \neq 0\]

\[\sin x \neq 0\ \]

\[2x \neq \frac{\pi}{2} + \pi n\]

\[x \neq \pi\text{n.\ \ }\]

\[\cos{2x} \neq 0\]

\[x \neq \frac{\pi}{4} + \frac{\pi n}{2}.\]

\[4)\ y = \frac{1}{\cos^{3}x + \cos x}\]

\[\cos^{3}x + \cos x \neq 0\]

\[\cos x \bullet \left( \cos^{2}x + 1 \right) \neq 0\]

\[\cos x \neq 0\]

\[x \neq \frac{\pi}{2} + \pi\text{n.}\]