Решебник по алгебре и начала математического анализа 11 класс Колягин Задание 165

\[1)\ f(x) = x^{2} - 2x + 1;\]

\[f^{'}(x) = 2x - 2;\]

\[f^{'}(0) = 0 - 2 = - 2;\]

\[f^{'}(2) = 4 - 2 = 2.\]

\[Ответ:\ - 2;\ 2.\]

\[2)\ f(x) = x^{3} - 2x;\]

\[f^{'}(x) = 3x^{2} - 2;\]

\[f^{'}(0) = 0 - 2 = - 2;\]

\[f^{'}(2) = 12 - 2 = 10.\]

\[Ответ:\ - 2;\ 10.\]

\[3)\ f(x) = - x^{3} + 2x^{2};\]

\[f^{'}(x) = - 3x^{2} + 2 \bullet 2x;\]

\[f^{'}(0) = 0 + 0 = 0;\]

\[f^{'}(2) = - 12 + 8 = - 4.\]

\[Ответ:\ \ 0;\ - 4.\]

\[4)\ f(x) = 3x^{2} + x + 1;\]

\[f^{'}(x) = 3 \bullet 2x + 1;\]

\[f^{'}(0) = 0 + 1 = 1;\]

\[f^{'}(2) = 12 + 1 = 13.\]

\[Ответ:\ \ 1;\ 13.\]