\[1)\ Расстояние\ между\ кораблями:\]
\[S(t) = \sqrt{(3t)^{2} + (5 - 4t)^{2}} =\]
\[= \sqrt{9t^{2} + 25 - 40t + 16t^{2}} =\]
\[= \sqrt{25t^{2} - 40t + 25}.\]
\[2)\ S^{'}(t) = \frac{\left( 25t^{2} \right)^{'} - (40t)^{'} + (25)^{'}}{2\sqrt{25t^{2} - 40t + 25}} =\]
\[= \frac{25 \bullet 2t - 40}{2\sqrt{25t^{2} - 40t + 25}}.\]
\[3)\ Промежуток\ возрастания:\]
\[25 \bullet 2t - 40 \geq 0\]
\[50t \geq 40\]
\[5t \geq 4\]
\[t \geq \frac{4}{5}.\]
\[4)\ Точка\ минимума:\]
\[S\left( \frac{4}{5} \right) = \sqrt{25 \bullet \frac{16}{25} - 40 \bullet \frac{4}{5} + 25} =\]
\[= \sqrt{16 - 32 + 25} = \sqrt{9} = 3.\]
\[Ответ:\ \ нет.\]