Решебник по алгебре и начала математического анализа 11 класс Алимов Задание 569

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$$1)2\arccos 0+3\arccos 1=$$

$$=2\bullet \frac{\pi }{2}+3\bullet 0=\pi +0=\pi$$

$$2)3\arccos (-1)-2\arccos 0=$$

$$=3(\pi -\arccos 1)-2\bullet \frac{\pi }{2}=$$

$$=3(\pi -0)-\pi =$$

$$=3\pi -\pi =2\pi$$

$$=12\bullet \frac{\pi }{6}-3(\pi -\arccos \frac{1}{2})=$$

$$=2\pi -3(\pi -\frac{\pi }{3})=$$

$$=2\pi -3\pi +\pi =0$$

$$=4(\pi -\frac{\pi }{4})+6(\pi -\frac{\pi }{6})=$$

$$=4\pi -\pi +6\pi -\pi =8\pi$$