Решебник по алгебре и начала математического анализа 11 класс Алимов Задание 1242

\[\boxed{\mathbf{1242}\mathbf{.}}\]

\[= \frac{1012}{100} - \frac{36}{10} \bullet \left( \frac{215}{100} + \frac{5}{100} \right) + \frac{2000}{100} =\]

\[= \frac{3012}{100} - \frac{36}{10} \bullet \frac{220}{100} =\]

\[= \frac{3012}{100} - \frac{7920}{1000} = \frac{3012}{100} - \frac{792}{100} =\]

\[= \frac{2220}{100} = 22,2\]

\[= \frac{962}{100} - \left( \frac{1062}{100} + \frac{90}{100} \right) \bullet \frac{10}{12} + 1 =\]

\[= \frac{962}{100} - \frac{1152}{100} \bullet \frac{10}{12} + 1 =\]

\[= \frac{962}{100} - \frac{960}{100} + \frac{100}{100} = \frac{102}{100} = 1,02\]