\[\boxed{\mathbf{854}\mathbf{.}}\]
\[g(x) = f^{'}(x) + f(x) + 2\]
\[f(x) = x\sin{2x}\ x = \pi:\ \]
\[f^{'}(x) =\]
\[= (x)^{'} \bullet \sin{2x} + x \bullet \left( \sin{2x} \right)^{'} =\]
\[= \sin{2x} + x \bullet 2 \bullet \cos{2x}.\]
\[= 0 + 2\pi \bullet 1 + \pi \bullet 0 + 2 = 2\pi + 2 =\]
\[= 2(\pi + 1).\]
\[Ответ:\ \ 2(\pi + 1).\]