Решебник по алгебре и начала математического анализа 10 класс Алимов Задание 1321

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\[1)\ \frac{3x - 16}{12} + 1 = \frac{x + 6}{4} - \frac{x + 3}{6}\ \ \ | \bullet 12\]

\[3x - 16 + 12 = 3(x + 6) - 2(x + 3)\]

\[3x - 4 = 3x + 18 - 2x - 6\]

\[3x - 4 = x + 12\]

\[2x = 16\]

\[x = 8.\]

\[Ответ:\ \ x = 8.\]

\[2)\ \frac{5}{3}(x - 7) - 3x - \frac{6(x - 8)}{7} =\]

\[= - \left( x + \frac{43}{3} \right)\ \ \ \ \ | \bullet 21\]

\[35(x - 7) - 63x - 18(x - 8) =\]

\[= - 21x - 301\]

\[35x - 245 - 63x - 18x + 144 =\]

\[= - 21x - 301\]

\[- 46x - 101 = - 21x - 301\]

\[- 25x = - 200\]

\[x = 8.\]

\[Ответ:\ \ x = 8.\]