Решебник по алгебре и начала математического анализа 10 класс Алимов Задание 1095

\[\boxed{\mathbf{1095}\mathbf{.}}\]

\[3)\ C_{6}^{1} + C_{6}^{2} + C_{6}^{3} + C_{6}^{4} + C_{6}^{5} =\]

\[= 2^{6} - C_{6}^{0} - C_{6}^{6} = 64 - 1 - 1 =\]

\[= 62;\]

\[4)\ C_{7}^{6} + C_{7}^{5} + C_{7}^{4} + C_{7}^{3} + C_{7}^{2} + C_{7}^{1} =\]

\[= 2^{7} - C_{7}^{7} - C_{7}^{0} = 128 - 1 - 1 =\]

\[= 126;\]

\[5)\ C_{9}^{0} + C_{9}^{1} + C_{9}^{2} + C_{9}^{3} + C_{9}^{4} =\]

\[= \frac{1}{2} \bullet 2^{9} = 2^{8} = 256;\]

\[= \frac{1}{2} \bullet 2^{11} = 2^{10} = 1024.\]