Решебник по алгебре и начала математического анализа 10 класс Алимов Задание 1065

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\[1)\ \frac{26!}{25!} = \frac{26 \bullet 25!}{25!} = 26\]

\[2)\ \frac{32!}{31!} = \frac{32 \bullet 31!}{31!} = 32;\]

\[3)\ \frac{12!}{10!} = \frac{12 \bullet 11 \bullet 10!}{10!} =\]

\[= 12 \bullet 11 = 132;\]

\[4)\ \frac{14!}{12!} = \frac{14 \bullet 13 \bullet 12!}{12!} = 14 \bullet 13 =\]

\[= 182;\]

\[5)\ \frac{5! \bullet 3!}{7!} = \frac{5! \bullet 3 \bullet 2}{7 \bullet 6 \bullet 5!} = \frac{6}{7 \bullet 6} = \frac{1}{7};\]

\[6)\ \frac{6! \bullet 4!}{8!} = \frac{6! \bullet 4 \bullet 3 \bullet 2}{8 \bullet 7 \bullet 6!} = \frac{8 \bullet 3}{8 \bullet 7} =\]

\[= \frac{3}{7};\]

\[7)\ \frac{10!}{8! \bullet 3!} = \frac{10 \bullet 9 \bullet 8!}{8! \bullet 3 \bullet 2} = 5 \bullet 3 =\]

\[= 15;\]

\[8)\ \frac{11!}{9! \bullet 2!} = \frac{11 \bullet 10 \bullet 9!}{9! \bullet 2} =\]

\[= 11 \bullet 5 = 55.\]