Решебник по алгебре и начала математического анализа 10 класс Колягин Задание 932

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Задание 932

\[\boxed{\mathbf{932.}}\]

\[Градусы\] \[0,5\] \[36\] \[159\] \[108\] \[150\] \[54\] \[\frac{450}{\pi}\] \[\frac{324}{\pi}\]
\[Радианы\] \[\frac{\pi}{360}\] \[\frac{\pi}{5}\] \[\frac{53\pi}{60}\] \[\frac{3\pi}{5}\] \[\frac{5}{6}\pi\] \[\frac{3}{10}\pi\] \[2,5\] \[1,8\]

\[0,5{^\circ} = \frac{\pi \bullet 0,5}{180} = \frac{\pi}{360}\]

\[36{^\circ} = \frac{\pi \bullet 36}{180} = \frac{\pi}{5}\]

\[159{^\circ} = \frac{\pi \bullet 159}{180} = \frac{53\pi}{60}\]

\[108{^\circ} = \frac{\pi \bullet 108}{180} = \frac{3\pi}{5}\]

\[\frac{5}{6}\pi = \left( \frac{180}{\pi} \bullet \frac{5\pi}{6} \right)^{{^\circ}} = (30 \bullet 5){^\circ} =\]

\[= 150{^\circ}\]

\[\frac{3}{10}\pi = \left( \frac{180}{\pi} \bullet \frac{3\pi}{10} \right)^{{^\circ}} =\]

\[= (18 \bullet 3){^\circ} = 54{^\circ}\]

\[2,5 = \left( \frac{180}{\pi} \bullet 2,5 \right)^{{^\circ}} = \left( \frac{450}{\pi} \right)^{{^\circ}}\]

\[1,8 = \left( \frac{180}{\pi} \bullet 1,8 \right)^{{^\circ}} = \left( \frac{324}{\pi} \right)^{{^\circ}}\]

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