Решебник по алгебре и начала математического анализа 10 класс Колягин Задание 225

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\[1)\ \left\{ 1;2;3;4;6;12 \right\};\]

\[2)\ \left\{ 1;2;5;10 \right\};\]

\[3)\ \left\{ - 4;\ - 3;\ - 2;\ - 1;0 \right\};\]

\[4)\ \left\{ \begin{matrix} x^{2} - 2x + 1 \leq 0 \\ x > 0\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \\ \end{matrix} \right.\ \text{\ \ \ }\]

\[\ \left\{ \begin{matrix} (x - 1)^{2} \leq 0 \\ x > 0\ \ \ \ \ \ \ \ \ \ \ \ \ \ \\ \end{matrix} \right.\ \text{\ \ \ \ \ }\left\{ \begin{matrix} x = 1 \\ x > 0 \\ \end{matrix} \right.\ \]

\[x = \left\{ 1 \right\}.\]

\[5)\ x = \left\{ - 2;3 \right\}.\]

\[6)\ \left\lbrack \begin{matrix} 2x^{2} - x + 3 = 0 \\ - x + 1 = 0\ \ \ \ \ \ \ \ \ \\ \end{matrix} \right.\ \]

\[2x^{2} - x + 3 = 0\]

\[D = 1 - 24 < 0 - нет\ корней.\]

\[- x + 1 = 0\]

\[x = 1.\]

\[x = \left\{ 1 \right\}.\]