Решебник по алгебре и начала математического анализа 10 класс Колягин Задание 167

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\[1)\ 2x + 1 = \frac{1}{x}\]

\[y = 2x + 1;\]

\[y = \frac{1}{x}.\]

\[x = - 1;\ \ x = 0,5.\]

\[2)\ 1 - x = - \frac{2}{x}\]

\[y = 1 - x;\]

\[y = - \frac{2}{x}.\]

\[x = - 1;\ \ x = 2.\]

\[3)\ x^{2} + 2 = \frac{3}{x}\]

\[y = x^{2} + 2;\]

\[y = \frac{3}{x}.\]

\[x = 1.\]

\[4)\ \sqrt{x + 1} = x^{2} - 1\]

\[y = \sqrt{x + 1};\]

\[y = x^{2} - 1.\]

\[x = - 1;\ \ x = 1,5.\]