Упростите выражение 16x^2/(4x-3)+9/(3-4x)-4x-5.

Ответ:

\[\frac{16x^{2}}{4x - 3} + \frac{9}{3 - 4x} - 4x - 5 =\]

\[= \frac{16x^{2}}{4x - 3} - \frac{9}{4x - 3} - (4x + 5)^{\backslash 4x - 3} =\]

\[= \frac{16x^{2} - 9 - 16x^{2} - 20x + 12x + 15}{4x - 3} =\]

\[= \frac{- 8x + 6}{4x - 3} = \frac{- 2 \cdot (4x - 3)}{4x - 3} = - 2.\]

\[Ответ:\ - 2.\]