Упростите выражение 16x^2/(4x-1)+1/(1-4x)-4x-4.

Ответ:

\[\frac{16x^{2}}{4x - 1} + \frac{1}{1 - 4x} - 4x - 4 =\]

\[= \frac{16x^{2}}{4x - 1} - \frac{1}{4x - 1} - (4x + 4)^{\backslash 4x - 1} =\]

\[= \frac{16x^{2} - 1 - 16x^{2} - 16x + 4x + 4}{4x - 1} =\]

\[= \frac{- 12x + 3}{4x - 1} = \frac{- 3 \cdot (4x - 1)}{4x - 1} = - 3.\]

\[Ответ:\ - 3.\]