Решите систему неравенств 6x+4>=0; 3x-2<=1

Ответ:

\[\ \left\{ \begin{matrix} 6x + 4 \geq 0 \\ 3x - 2 \leq 1 \\ \end{matrix}\text{\ \ \ \ \ \ \ \ } \right.\ \left\{ \begin{matrix} 6x \geq - 4 \\ 3x \leq 3\ \ \ \\ \end{matrix}\text{\ \ \ \ \ } \right.\ \left\{ \begin{matrix} x \geq - \frac{2}{3} \\ x \leq 1\ \ \ \\ \end{matrix} \right.\ \]

\[Ответ:\ \ \ x \in \left\lbrack - \frac{2}{3};\ \ \ 1 \right\rbrack.\]

\[\ |11 + 10x| = 1\]

\[11 + 10x = 1\ \ \ \ \ \ \ \ \ \ \ \ 11 + 10x = - 1\]

\[10x = - 10\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ 10x = - 12\]

\[x = - 1\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ x = - 1,2\]

\[Ответ:\ \ \ \ \ x = - 1\ \ \ \ \ и\ \ \ x = - 1,2.\]