Решите неравенство: x² + 4x – 32 < 0.

Ответ:

\[x^{2} + 4x - 32 < 0\]

\[x^{2} + 4x - 32 = 0\]

\[D = 4 + 32 = 36\]

\[x_{1} = - 2 + 6 = 4;\]

\[x_{2} = - 2 - 6 = - 8.\]

\[(x + 8)(x - 4) < 0\]

\[x \in ( - 8;4).\]