Решите неравенство: x^2+7x-8>=0.

Ответ:

\[x^{2} + 7x - 8 \geq 0\]

\[x_{1} + x_{2} = - 7;\ \ x_{1} \cdot x_{2} = - 8\]

\[x_{1} = - 8;\ \ x_{2} = 1.\]

\[(x + 8)(x - 1) \geq 0\]

\[x \leq - 8;\ \ x \geq 1.\]

\[Ответ:x \leq - 8;\ \ x \geq 1.\]