\[\frac{6b - 5}{b^{2} - 9} - \frac{2b + 9}{9 - b^{2}} + \frac{5 - 3b}{b^{2} - 9} =\]
\[= \frac{6b - 5 + 2b + 9 + 5 - 3b}{b^{2} - 9} =\]
\[= \frac{5b + 9}{b^{2} - 9}\]