\[\frac{a^{2} - x^{2}}{b^{2} - 16} \cdot \frac{b + 4}{a - x} + \frac{x}{4 - b} = \frac{a}{b - 4}\]
\[1.\ \ \frac{(a - x)(a + x) \cdot (b + 4)}{(b - 4)(b + 4)(a - x)} =\]
\[= \frac{a + x}{b - 4}\]
\[2.\ \ \frac{a + x}{b - 4} + \frac{x}{4 - b} = \frac{a + x - x}{b - 4} =\]
\[= \frac{a}{b - 4}\]