\[\frac{4 - 3b}{b^{2} - 2b} + \frac{3}{b - 2} =\]
\[= \frac{4 - 3b}{b(b - 2)} + \frac{3^{\backslash b}}{b - 2} =\]
\[= \frac{4 - 3b + 3b}{b(b - 2)} = \frac{4}{b^{2} - 2b}.\]