\[1\frac{1}{35} \cdot^{2}\left( 7 -^{1}5\frac{4}{9} \right) = 1\frac{3}{5}\]
\[1)\ 7 - 5\frac{4}{9} = 6\frac{9}{9} - 5\frac{4}{9} = 1\frac{5}{9}\]
\[2)\ 1\frac{1}{35} \cdot 1\frac{5}{9} = \frac{36}{35} \cdot \frac{14}{9} = \frac{4 \cdot 9 \cdot 7 \cdot 2}{5 \cdot 7 \cdot 9} = \frac{8}{5} =\]
\[= 1\frac{3}{5}\]