\[3^{- 2} + 6^{- 1} = \frac{1}{3^{2}} + \frac{1}{6} =\]
\[= \frac{1^{\backslash 2}}{9} + \frac{1^{\backslash 3}}{6} = \frac{2 + 3}{18} = \frac{5}{18}.\]