\[\frac{{2,45}^{2} + 4,9 \bullet 3,55 + {3,55}^{2}}{{4,23}^{2} - 4,23 \bullet 2,46 + {1,23}^{2}} =\]
\[= \frac{(2,45 + 3,55)^{2}}{(4,23 - 1,23)^{2}} = \frac{6^{2}}{3^{2}} = \frac{36}{9} = 4\]