3) y=x/2
4) y=2/x
\[А\] | \[Б\] | \[В\] |
---|---|---|
\[4\] | \[2\] | \[1\] |
\[5;\ \ 2;\ - 1;\ldots\]
\[a_{1} = 5;\ \ a_{2} = 2:\]
\[d = 2 - 5 = - 3.\]
\[S_{6} = \frac{2a_{1} + d(n - 1)}{2} \cdot n =\]
\[= \frac{2 \cdot 5 - 3 \cdot (6 - 1)}{2} \cdot 6 =\]
\[= (10 - 3 \cdot 5) \cdot 3 = - 5 \cdot 3 = - 15.\]
\[Ответ:\ - 15.\]
\[\frac{16x^{2}}{4x - 3} + \frac{9}{3 - 4x} - 4x - 5 =\]
\[= \frac{16x^{2}}{4x - 3} - \frac{9}{4x - 3} - (4x + 5)^{\backslash 4x - 3} =\]
\[= \frac{16x^{2} - 9 - 16x^{2} - 20x + 12x + 15}{4x - 3} =\]
\[= \frac{- 8x + 6}{4x - 3} = \frac{- 2 \cdot (4x - 3)}{4x - 3} = - 2.\]
\[Ответ:\ - 2.\]
\[\frac{2x + 1}{x - 3} \leq 1^{\backslash x - 3}\]
\[\frac{2x + 1 - x + 3}{x - 3} \leq 0\]
\[\frac{x + 4}{x - 3} \leq 0;\ \ \ \ x
eq 3\]
\[- 4 \leq x < 3.\]
\[Ответ:2.\]
\[Ответ:1.\]
\[Ответ:\ - 3{^\circ}С.\]
\[9200\ рублей - 115\%\]
\[x\ рублей - 100\%\]
\[x = \frac{9200 \cdot 100}{115} = 80 \cdot 100 =\]
\[= 8000\ (рублей) - положили\ на\ счет.\]
\[Ответ:8000\ рублей.\]