\[\frac{a^{2} - 9}{2a + 8} \cdot \frac{4a + 16}{a^{2} + 6a + 9} =\]
\[= \frac{(a - 3)(a + 3) \cdot 4 \cdot (a + 4)}{2 \cdot (a + 4)(a + 3)^{2}} = \frac{2 \cdot (a - 3)}{a + 3}\]
\[При\ a = 1,8:\]
\[\frac{2 \cdot (1,8 - 3)}{1,8 + 3} = \frac{2 \cdot ( - 1,2)}{4,8} = - \frac{2,4}{4,8} = - \frac{24}{48} =\]
\[= - \frac{1}{2} = - 0,5.\]