\[\frac{3x - 2}{2x - 6} - \frac{3x + 2}{3x - 9} - \frac{3x - 8}{18 - 6x} =\]
\[= \frac{3x - 2^{\backslash 3}}{2(x - 3)} - \frac{3x + 2^{\backslash 2}}{3(x - 3)} - \frac{3x - 8}{6(3 - x)} =\]
\[= \frac{9x - 6 - 6x - 4 + 3x - 8}{6(x - 3)} =\]
\[= \frac{6x - 18}{6(x - 3)} = \frac{6(x - 3)}{6(x - 3)} = 1\]