Упростите выражение 3√x (1/(√x-4)+1/(√x+4))+96/(16-x).

\[3\sqrt{x}\left( \frac{1^{\text{√}x + 4\ }}{\sqrt{x} - 4} + \frac{1^{\text{√}x - 4}}{\sqrt{x} + 4} \right) + \frac{96}{16 - x} =\]

\[= 3\sqrt{x} \cdot \frac{\sqrt{x} + 4 + \sqrt{x} - 4}{x - 16} - \frac{96}{x - 16} =\]

\[= \frac{3\sqrt{x} \cdot 2\sqrt{x} - 96}{x - 16} = \frac{6x - 96}{x - 16} =\]

\[= \frac{6 \cdot (x - 16)}{x - 16} = 6.\]