\[\left( \frac{a^{7}}{d^{- 3}} \right)^{- 4} \cdot \left( \frac{a^{- 3}}{d^{9}} \right)^{- 12} =\]
\[= \frac{a^{- 28}}{d^{12}} \cdot \frac{a^{36}}{d^{- 108}} = \frac{a^{8}}{d^{- 96}} = a^{8}d^{96}.\]