\[\frac{y^{2} + 3y + 2}{4y + 4} = \frac{(y + 2)(y + 1)}{4(y + 1)} =\]
\[= \frac{y + 2}{4}.\]
\[y^{2} + 3y + 2 = (y + 2)(y + 1)\]
\[y_{1} + y_{2} = - 3;y_{1} \cdot y_{2} = 2\]
\[y_{1} = - 2;\ \ y_{2} = - 1.\]