Сократите дробь: (b^2+6b+9)/(b^2-9).

\[\frac{b^{2} + 6b + 9}{b^{2} - 9} = \frac{(b + 3)^{2}}{(b - 3)(b + 3)} =\]

\[= \frac{b + 3}{b - 3}\]