Сократите дробь: (4x^2+7x-2)/(16x^2-1).

\[\frac{4x^{2} + 7x - 2}{16x^{2} - 1} = \frac{(4x - 1)(x + 2)}{(4x - 1)(4x + 1)} =\]

\[= \frac{x + 2}{4x + 1}.\]

\[4x^{2} + 7x - 2 =\]

\[= 4\left( x - \frac{1}{4} \right)(x + 2) =\]

\[= (4x - 1)(x + 2)\]

\[D = 49 + 32 = 81\]

\[x_{1} = \frac{- 7 + 9}{8} = \frac{2}{8} = \frac{1}{4};\]

\[x_{2} = \frac{- 7 - 9}{8} = - 2.\]