Сократите дробь: (3+√3)/(√2+√6).

\[\frac{3 + \sqrt{3}}{\sqrt{2} + \sqrt{6}} = \frac{\sqrt{3}\left( \sqrt{3} + 1 \right)}{\sqrt{2}\left( 1 + \sqrt{3} \right)} = \frac{\sqrt{3}}{\sqrt{2}} = \frac{\sqrt{6}}{2}\]