Сократите дробь: (16-2x)/(8+7x-x^2).

\[\frac{16 - 2x}{8 + 7x - x^{2}} = - \frac{2(8 - x)}{x^{2} - 7x - 8} =\]

\[= \frac{2 \cdot (x - 8)}{(x + 1)(x - 8)} = \frac{2}{x + 1}\]

\[x^{2} - 7x - 8 = (x - 8)(x + 1)\]

\[x_{1} + x_{2} = 7;\ \ \ x_{1} \cdot x_{2} = - 8\]

\[x_{1} = 8;\ \ x_{2} = - 1.\]