\[\frac{12x^{2} + x - 1}{9x^{2} + 6x + 1} =\]
\[= \frac{(3x + 1)(4x - 1)}{(3x + 1)^{2}} = \frac{4x - 1}{3x + 1}.\]
\[12x^{2} + x - 1 =\]
\[= 12\left( x + \frac{1}{3} \right)\left( x - \frac{1}{4} \right) =\]
\[= (3x + 1)(4x - 1)\]
\[D = 1 + 48 = 49\]
\[x_{1} = \frac{- 1 + 7}{24} = \frac{6}{24} = \frac{1}{4};\]
\[x_{2} = \frac{- 1 - 7}{24} = - \frac{8}{24} = - \frac{1}{3}.\]