Решите уравнение: x/(x+2)-4/(x^2+2x)=0.

\[\frac{x}{x + 2} - \frac{4}{x^{2} + 2x} = 0\]

\[\frac{x^{\backslash x}}{x + 2} - \frac{4}{x(x + 2)} = 0\]

\[\frac{x^{2} - 4}{x(x + 2)} = 0;\ \ x \neq 0;x \neq - 2\]

\[\frac{(x - 2)(x + 2)}{x(x + 2)} = 0\]

\[\frac{x - 2}{x} = 0\]

\[x - 2 = 0\]

\[x = 2.\]

\[Ответ:x = 2.\]