Решите уравнение: (x-4)(x+3)+(x+3)(x-2)=0.

\[(x - 4)(x + 3) + (x + 3)(x - 2) = 0\]

\[x^{2} - 4x + 3x - 12 + x^{2} + 3x - 2x - 6 = 0\]

\[2x^{2} - 18 = 0\]

\[2x^{2} = 18\]

\[x^{2} = 9\]

\[x = \pm 3.\]

\[Ответ:x = \pm 3.\]