Решите уравнение: x^5+4x^4+4x^3-x^2-4x-4=0.

\[(x + 2)^{2}\left( x^{3} - 1 \right) = 0\]

\[x + 2 = 0\ \ \ \ \ \ \ \ \ x^{3} - 1 = 0\]

\[x = - 2\ \ \ \ \ \ \ \ \ \ \ \ \ x^{3} = 1\]

\[\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ x = 1\]

\[Ответ:\ x = - 2;x = 1.\]