Решите уравнение x^4-x^3-7x^2+x+6=0.

\[x^{4} - x^{3} - 7x^{2} + x + 6 = 0\]

\[x = 1.\]

\[Разделим\ на\ (x - 1):\]

\[x^{3} - 7x - 6 = 0\]

\[x = - 1.\]

\[Разделим\ на\ (x + 1):\]

\[x^{2} - x - 6 = 0\]

\[x_{1} + x_{2} = 1;\ \ x_{1} \cdot x_{2} = - 6\]

\[x_{1} = 3;\ \ x_{2} = - 2.\]

\[Ответ:x = \pm 1;x = - 2;x = 3.\]