Решите уравнение: x^3-5x=4x^2.

\[x^{3} - 5x = 4x^{2}\]

\[x^{3} - 4x^{2} - 5x = 0\]

\[x\left( x^{2} - 4x - 5 \right) = 0\]

\[1)\ x = 0;\]

\[2)\ x^{2} - 4x - 5 = 0\]

\[D_{1} = 4 + 5 = 9\]

\[x_{1} = 2 + 3 = 5;\ \]

\[x_{2} = 2 - 3 = - 1.\]

\[Ответ:\ - 1;0;5.\]