Решите уравнение: x^3-4x^2-9x+36=0.

\[x^{3} - 4x^{2} - 9x + 36 = 0\]

\[x^{2}(x - 4) - 9(x - 4) = 0\]

\[(x - 4)\left( x^{2} - 9 \right) = 0\]

\[(x - 4)(x - 3)(x + 3) = 0\]

\[x = 4;\ \ x = 3;\ \ x = - 3.\]

\[Ответ:\ \ x = \pm 3;\ \ x = 4.\]