Решите уравнение: x^3-2x^2-2x-3=0.

\[x³ - 2x^{2} - 2x - 3 = 0\]

\[P(3) = 3^{3} - 2 \bullet 3^{2} - 2 \bullet 3 - 3 =\]

\[= 27 - 18 - 6 - 3 = 0\]

\[(x - 3)\left( x^{2} + x + 1 \right) = 0\]

\[x - 3 = 0\]

\[x = 3.\]

\[x^{2} + x + 1 = 0\]

\[D = 1^{2} - 4 \bullet 1 \bullet 1 = 1 - 4 =\]

\[= - 3 < 0 \Longrightarrow нет\ решения.\]

\[Ответ:3.\]