Решите уравнение: (x^2-8x+5)-(6x^2+7x-1)=4-9x-5x^2.

\[\left( x^{2} - 8x + 5 \right) - \left( 6x^{2} + 7x - 1 \right) = 4 - 9x - 5x^{2}\]

\[x^{2} - 8x + 5 - 6x^{2} - 7x + 1 - 4 + 9x + 5x^{2} = 0\]

\[- 6x + 6 = 0\]

\[- 6x = - 6\]

\[x = 1.\]

\[Ответ:x = 1.\]