Решите уравнение: (x^2-6x-4)/3=11x/10+1.

\[\frac{x^{2} - 6x - 4}{3} = \frac{11x}{10} + 1\ \ \ \ \ \ | \cdot 30\]

\[10x^{2} - 60x - 40 = 33x + 30\]

\[10x^{2} - 93x - 70 = 0\]

\[D = 8649 + 2800 = 11\ 449 =\]

\[= 107^{2}\]

\[x_{1} = \frac{93 - 107}{20} = - \frac{14}{20} =\]

\[= - \frac{70}{100} = - 0,7;\ \ \]

\[x_{2} = \frac{93 + 107}{20} = \frac{200}{20} = 10.\]