\[x^{2} - 6x - 16 = 0\]
\[x_{1} + x_{2} = 6;\ \ \ x_{1} \cdot x_{2} = - 16\]
\[x_{1} = 8;\ \ \ x_{2} = - 2.\]
\[Ответ:x = - 2;\ \ x = 8.\]